Use print() function in both Python 2 and Python 3
Legacy __print__ statements are syntax errors in Python 3 but __print()__ function works as expected in both Python 2 and Python 3.
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@@ -41,6 +41,7 @@ from __future__ import with_statement
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"""
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Decrypt Barnes & Noble encrypted ePub books.
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"""
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from __future__ import print_function
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__license__ = 'GPL v3'
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__version__ = "4.1"
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@@ -262,7 +263,7 @@ def decryptBook(keyb64, inpath, outpath):
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namelist = set(inf.namelist())
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if 'META-INF/rights.xml' not in namelist or \
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'META-INF/encryption.xml' not in namelist:
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print u"{0:s} is DRM-free.".format(os.path.basename(inpath))
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print(u"{0:s} is DRM-free.".format(os.path.basename(inpath)))
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return 1
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for name in META_NAMES:
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namelist.remove(name)
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@@ -272,7 +273,7 @@ def decryptBook(keyb64, inpath, outpath):
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expr = './/%s' % (adept('encryptedKey'),)
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bookkey = ''.join(rights.findtext(expr))
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if len(bookkey) != 64:
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print u"{0:s} is not a secure Barnes & Noble ePub.".format(os.path.basename(inpath))
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print(u"{0:s} is not a secure Barnes & Noble ePub.".format(os.path.basename(inpath)))
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return 1
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bookkey = aes.decrypt(bookkey.decode('base64'))
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bookkey = bookkey[:-ord(bookkey[-1])]
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@@ -315,7 +316,7 @@ def decryptBook(keyb64, inpath, outpath):
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pass
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outf.writestr(zi, decryptor.decrypt(path, data))
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except:
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print u"Could not decrypt {0:s} because of an exception:\n{1:s}".format(os.path.basename(inpath), traceback.format_exc())
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print(u"Could not decrypt {0:s} because of an exception:\n{1:s}".format(os.path.basename(inpath), traceback.format_exc()))
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return 2
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return 0
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@@ -326,13 +327,13 @@ def cli_main():
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argv=unicode_argv()
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progname = os.path.basename(argv[0])
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if len(argv) != 4:
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print u"usage: {0} <keyfile.b64> <inbook.epub> <outbook.epub>".format(progname)
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print(u"usage: {0} <keyfile.b64> <inbook.epub> <outbook.epub>".format(progname))
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return 1
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keypath, inpath, outpath = argv[1:]
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userkey = open(keypath,'rb').read()
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result = decryptBook(userkey, inpath, outpath)
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if result == 0:
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print u"Successfully decrypted {0:s} as {1:s}".format(os.path.basename(inpath),os.path.basename(outpath))
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print(u"Successfully decrypted {0:s} as {1:s}".format(os.path.basename(inpath),os.path.basename(outpath)))
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return result
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def gui_main():
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